T s=1/(15000×2048)s=1/30720000s=32.552083ns
where
15Khz is subcarrier band in LTE
2048 : block size
look for 3gpp 36.211.
Hi Guys,
I'm studing 4G but I can not understand why Ts is about 32.552083 ns.
Please is there anyone who could explain me why Ts has this value ?
Reputation will be given to helpful answers.
Thanks in advance.
Handover24
Last edited by Handover24; 2013-03-12 at 11:02 PM
T s=1/(15000×2048)s=1/30720000s=32.552083ns
where
15Khz is subcarrier band in LTE
2048 : block size
look for 3gpp 36.211.
thank you very much indeed topoffenders it is so simple :-) and I was not able to understand
@Hanover24
For your further study of this topic, read chapter 3.5 of Book LTE in Bullet.
Enjoy
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