LTE why Ts=32.55 ns ???

Hi Guys,
I'm studing 4G but I can not understand why Ts is about 32.552083 ns.
Please is there anyone who could explain me why Ts has this value ?
Reputation will be given to helpful answers.
Thanks in advance.
Handover24

T s=1/(15000×2048)s=1/30720000s=32.552083ns
where
15Khz is subcarrier band in LTE
2048 : block size

look for 3gpp 36.211.

thank you very much indeed topoffenders it is so simple :-) and I was not able to understand

Quote:

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Originally Posted by Handover24

thank you very much indeed topoffenders it is so simple :-) and I was not able to understand

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not a problem my friend, that what we are here for, sharing..

@Hanover24
For your further study of this topic, read chapter 3.5 of Book LTE in Bullet.
Enjoy

Quote:

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Originally Posted by topoffenders

T s=1/(15000×2048)s=1/30720000s=32.552083ns
where
15Khz is subcarrier band in LTE
2048 : block size

look for 3gpp 36.211.

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And what if we have 10Mhz bandwidth and FFT size 1024?

Quote:

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Originally Posted by Mctest

And what if we have 10Mhz bandwidth and FFT size 1024?

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And one more question,if we have Ts which depends on sampling rate,so does it mean that timing advanced also depends on this variable,because Ta=16Ts?