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Armagadon
2010-04-24, 02:43 PM
Hello friends,

Can any one describe the difference between Ec/No and Eb/Io? and If we have Ec/No provided, how can we deduct the Eb/Io??

Regards

rapdoc
2010-04-25, 12:33 AM
Hi friends
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onlygod
2010-04-26, 05:21 AM
As far as I understand it, in an ideal situation (no external noise etc) there should be no difference between Ec/No and Ec/Io.

My understanding is that Ec/No is Energy of the Chip / Noise. This noise can be noise created by the 3G cell itself as the traffic increases, external noise source, other 3G cells causing a noise increase (pilot pollution). While Ec/Io is the Energy of the Chip / the noise made by this cell only.

Blacktiger
2010-05-28, 07:42 AM
Please can anyone explain in Details...

rosan
2010-05-28, 11:02 AM
"OnlyGod" is correct, if mathematically speaking

Ec/No = Ec/Io x Processing Gain

gprastomo
2010-05-28, 09:39 PM
Hi,

Simply speaking,
EcNo = is on the air, all spectrum is spread, so you can have negative value over total noise.
EbNo = is on the base band after despread, only 1 user is decoded so you will have positif value over total noise

edinburgh
2010-05-28, 11:24 PM
Again Eb/No is vendor related parameters for different bearers (based on channel model).

where Ec/No is normally considered in pilot channel and constant value. (-15 ~ -18 dB)

In link budget calculation, both parameters are considered to find out MAPL.

firstmaxim
2010-06-20, 11:26 PM
Hello friends,

Can any one describe the difference between Ec/No and Eb/Io? and If we have Ec/No provided, how can we deduct the Eb/Io??

Regards
Ec/Io is measured before despreading. Eb/No is measured after despreading and is very much a vendor related parameter. But, it can also vary based on environment (rural, urban... based on the delay spread) vehicular speed, diversity , application, use of power control , FEC...

Regards.

firstmaxim
2010-06-20, 11:28 PM
"OnlyGod" is correct, if mathematically speaking

Ec/No = Ec/Io x Processing Gain
This is wrong; It should be
Eb/No = Ec/Io x Processing Gain

josogun2
2010-06-24, 04:14 PM
@fistmaxim

i think your answer is correct.