mounir34
2020-07-08, 03:26 PM
dears
Example: Let us consider BW =100 MHzLet
--SCS = 30 KHzi.e. 1 slot = 0.5 ms =14 symbols, 1 ms = 28 symbols
--1 PRB = 12 * 28 =336 symbols
--No of PRBs in 100MHz BW for 30 KHz SCS = 273
--MCS = 256 QAM i.e.1 symbol represents 8 bits.
--Code Rate = 948/1024= 0.92578125
--Mo of MIMO Layers =4 and Control channel overhead = 14% i.e. Data (PDSCH) Symbols = (100-14) % =86%
--Max DL Data Rate = [(No of PRBs) * (No ofSymbols per PRB) * (% of PDSCH Symbols)* (Bits/Symbol)* (Code Rate)* (No ofMIMO Layers)] per ms = (273 * 336 * 0.86 * 8 * 0.92578125 * 4) per ms = 2337 Mbps or 2.337 Gbps
Example: Let us consider BW =100 MHzLet
--SCS = 30 KHzi.e. 1 slot = 0.5 ms =14 symbols, 1 ms = 28 symbols
--1 PRB = 12 * 28 =336 symbols
--No of PRBs in 100MHz BW for 30 KHz SCS = 273
--MCS = 256 QAM i.e.1 symbol represents 8 bits.
--Code Rate = 948/1024= 0.92578125
--Mo of MIMO Layers =4 and Control channel overhead = 14% i.e. Data (PDSCH) Symbols = (100-14) % =86%
--Max DL Data Rate = [(No of PRBs) * (No ofSymbols per PRB) * (% of PDSCH Symbols)* (Bits/Symbol)* (Code Rate)* (No ofMIMO Layers)] per ms = (273 * 336 * 0.86 * 8 * 0.92578125 * 4) per ms = 2337 Mbps or 2.337 Gbps