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atese
2009-04-10, 01:57 AM
Hi all.

Anyone have detailed information that explain why TSC must be the same that BCC.

I know that ETSI rules said that must be the same, but I´d like to know the tech reason.

Thanks in advance

ghassen
2009-04-10, 03:44 AM
Hi all.

Anyone have detailed information that explain why TSC must be the same that BCC.

I know that ETSI rules said that must be the same, but I´d like to know the tech reason.

Thanks in advance
we have 0-7 trainning sequences
in normal burst the trainning sequence (TSC) is 26 bits length
in synchro burst it's abouts 64 bits
training sequence is another tool to differenciate between different bts ie : 2 bts with same BCCH frequency and same BSIC will never have same training sequence
it's also used for averaging the error over the burst because the training sequence is separating 2 data blocks as showed below
-------------------------------------------------------------------------------
| T = bits | data = 57 bit | s = 1 | TSC = 26 | s = 1 | data | T = 3| GP = 8.25 bit |
-------------------------------------------------------------------------------
TSC is used also for BER estimation and calculating the adaptatif algorithm parameter for channel estimation too by the mean of a gliding window i don't know exactly which doc is discribing that in ETSI but i remember that i have already read that in some doc
these are the 16 bit in the middle of the training sequence the complete sequence can be obtained by repeating the 5th first and last bits
The used training sequences look as follows:
Training sequence No. Training sequence bits
1 (1,0,1,1,1,0,0,0,0,1,0,0,0,1,0,0)
2 (1,0,1,1,1,0,1,1,1,1,0,0,0,1,0,1)
3 (0,1,1,1,0,1,1,1,0,1,0,0,1,0,0,0)
4 (1,1,1,1,0,1,1,0,1,0,0,0,1,0,0,0)
5 (0,1,0,1,1,1,0,0,1,0,0,0,0,0,1,1)
6 (1,1,0,1,0,1,1,0,0,0,0,0,1,0,0,1)
7 (1,1,1,1,1,0,1,1,0,0,0,1,0,1,0,0)
8 (1,1,1,0,0,0,1,0,0,1,0,1,1,1,0,1)

here again i found the doc TS 23.003 describing the training sequence i will update each time when i find somethinf new to give you best answers

atese
2009-04-10, 05:30 AM
we have 0-7 trainning sequences
in normal burst the trainning sequence (TSC) is 26 bits length
in synchro burst it's abouts 64 bits
training sequence is another tool to differenciate between different bts ie : 2 bts with same BCCH frequency and same BSIC will never have same training sequence
it's also used for averaging the error over the burst because the training sequence is separating 2 data blocks as showed below
-------------------------------------------------------------------------------
| T = bits | data = 57 bit | s = 1 | TSC = 26 | s = 1 | data | T = 3| GP = 8.25 bit |
-------------------------------------------------------------------------------
TSC is used also for BER estimation and calculating the adaptatif algorithm parameter for channel estimation too by the mean of a gliding window i don't know exactly which doc is discribing that in ETSI but i remember that i have already read that in some doc
these are the 16 bit in the middle of the training sequence the complete sequence can be obtained by repeating the 5th first and last bits
The used training sequences look as follows:
Training sequence No. Training sequence bits
1 (1,0,1,1,1,0,0,0,0,1,0,0,0,1,0,0)
2 (1,0,1,1,1,0,1,1,1,1,0,0,0,1,0,1)
3 (0,1,1,1,0,1,1,1,0,1,0,0,1,0,0,0)
4 (1,1,1,1,0,1,1,0,1,0,0,0,1,0,0,0)
5 (0,1,0,1,1,1,0,0,1,0,0,0,0,0,1,1)
6 (1,1,0,1,0,1,1,0,0,0,0,0,1,0,0,1)
7 (1,1,1,1,1,0,1,1,0,0,0,1,0,1,0,0)
8 (1,1,1,0,0,0,1,0,0,1,0,1,1,1,0,1)

here again i found the doc TS 23.003 describing the training sequence i will update each time when i find somethinf new to give you best answers


Thank you ghassen.

Your explanation is very usefull.

But now I´ve got a new doubt...in the case of a pair of co-channel co-BSIC, we have have the same training sequence code in both sector, according to the ETSI rule TSC=BCC.....if this is correct, then there is not way to differenciate both sector.

We can set a TSC <> BCC to help MS to differenciate tho sectors co-channel co-BSIC. Is this a valid option no matter what ETSI said about it ?

Any comments are wellcome...

ghassen
2009-04-10, 09:38 AM
Thank you ghassen.

Your explanation is very usefull.

But now I´ve got a new doubt...in the case of a pair of co-channel co-BSIC, we have have the same training sequence code in both sector, according to the ETSI rule TSC=BCC.....if this is correct, then there is not way to differenciate both sector.

We can set a TSC <> BCC to help MS to differenciate tho sectors co-channel co-BSIC. Is this a valid option no matter what ETSI said about it ?

Any comments are wellcome...

timing advance can solve this i think also there is too many mean to discriminate between two cells

atese
2009-04-10, 12:50 PM
timing advance can solve this i think also there is too many mean to discriminate between two cells


Thank you ghassen.....

Keep in touch for next queries...

Regards

waleed
2009-06-02, 03:18 PM
great dear

k3group
2009-07-23, 10:30 PM
Hi Dear,

TSC is the fixed sequence which is known to both mobile and BTS and that is useful to understand the mobile and BTS that how is the radio environment deteriorate the bit level. Which is later on used as a correction factor. It is not the identity for the BTS.

RF engineer
2009-07-24, 12:01 AM
The reason is that the purpose of TSC is to estimate Radio Quality on BCCH TS or Traffic TS if TSC is not decoded it means the link is not good.and i did test for the effect on huawei and Alcatel .
In alcatel when both the same not effect but in huawei it effected but really i doot know why, may one of our collegues can have idea.
BR
RF

timedomain
2009-07-27, 04:21 AM
only as an idea,
if bcc and tsc will not be same how the comparison will be done to estimate rx qual,

before there is another question actually has to be answered: bcc and tsc are sent separately and are they compared for ber calculation i dont know.

electron
2009-07-27, 12:38 PM
When If TSC and BCC aren't same it has affect on Handover

crisnspro
2009-07-27, 11:15 PM
for one cell, you can set in same or not same. as usual, we set the BCCH slot's TSC equal BCC.