LTE RS power boost

Hi,

Could you support to know the reel Rs power using the below config:
MaxPower=46
Pb=1
Pa=-3
BW=10M

Thanks a lot

Reference Signal Power = 18.2dBm

Quote:

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Originally Posted by oucht79

Hi,

Could you support to know the reel Rs power using the below config:
MaxPower=46
Pb=1
Pa=-3
BW=10M

Thanks a lot

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Ok That a lot,
Actually my MaxPower=20W and i want to increase the power from 18.2 to 21.2, is there any issue if put Pa=-6/Pb=3?

not good idea. better play with thresholds or antenna tilt etc.

Quote:

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Originally Posted by oucht79

Ok That a lot,
Actually my MaxPower=20W and i want to increase the power from 18.2 to 21.2, is there any issue if put Pa=-6/Pb=3?

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Quote:

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Originally Posted by agenov

not good idea. better play with thresholds or antenna tilt etc.

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Why is the use of RS Power Boost a bad idea?

Just Change Rs Power to 212 and keep Pb=1 and Pa=-3, Max Power will increase to 40 W (46 dBm)
if you change Pb=3 and Pa=-6 with Rs=212, Max Power will remain 20W (43 dBm), coverage will increase but less power allocation for PDSCH type A

btw please don't forget to consider single / dual carrier in your power calculation

Quote:

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Originally Posted by oucht79

Hi,

Could you support to know the reel Rs power using the below config:
MaxPower=46
Pb=1
Pa=-3
BW=10M

Thanks a lot

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Hello,
the idea of LTE is to have same power for each RE So the RE power is 80 watts/(Number of RB *12) which in you case will be 21.25 dBm
pa is the power addition and reduction on CRS so you will have 21.25-3=18.25 dBm
pb is the power reduction.addition to Type-B RE (symbols which are including RS)

this is not a good configuration which causes lower RS power and consequently lowercoverage and SINR
if you are using MIMO, it is better consider +3dB power addition in RS power to extend the coverage and better SINR

cheers

Very good explaination. Just to add pa represent those RE's which doesnt have RS symbols. pb are those RE's which contain RS RE's

Quote:

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Originally Posted by babak1349

Hello,
the idea of LTE is to have same power for each RE So the RE power is 80 watts/(Number of RB *12) which in you case will be 21.25 dBm
pa is the power addition and reduction on CRS so you will have 21.25-3=18.25 dBm
pb is the power reduction.addition to Type-B RE (symbols which are including RS)

this is not a good configuration which causes lower RS power and consequently lowercoverage and SINR
if you are using MIMO, it is better consider +3dB power addition in RS power to extend the coverage and better SINR

cheers

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Quote:

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Originally Posted by pathloss

Why is the use of RS Power Boost a bad idea?

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Huawei CRS
1.PDSCHCfg.ReferenceSignalPwr 18.2 dBm for 20 watt===>Pb
2.PDSCH Other PDSCHCfg.Pb CellDlpcPdschPa.Pa PcOff 1 dB to -3 dB===>Pa


E******* CRS
1.calculated from[SectorEquipmentFunction]configuredOutputPower[EUtranCellFDD] crsGain 40000 to 300 (3 dB)==>Pa
2.[EUtranCellFDD] pdschTypeBgain 1 ===>(Pb)


Nokia
1.CRS power calculated from [LNCEL] pMax[LNCEL] dlRsBoost 430 (20 watt) 1000 (0 dB)===>Pa